Tic-Tac-Toe Game for Two Players


# Assign the array that will hold the tic-tac-toe values to null  
choices = []

# Fill in the squares with numbers from 1 to 10
for x in range(0, 9):
	choices.append(str(x + 1))

playerOneTurn = True
winner = False

# Display the Tic-tac-toe board
print('\n -----')
print('|' + choices[0] + '|' + choices[1] + '|' + choices[2] + '|')
print(' -----')
print('|' + choices[3] + '|' + choices[4] + '|' + choices[5] + '|')
print(' -----')
print('|' + choices[6] + '|' + choices[7] + '|' + choices[8] + '|')
print(' -----\n')


# Keep playing while there is still no winner
while not winner:
	if playerOneTurn:
		print("Player 1:")
	else:
		print("Player 2:")

	# Allow the user to select a square
	choice = int(input(">> "))

	# If the user enters a value outside the range 1-10 display an error message and prompt the user to reenter again
	while (choice < 1) or (choice > 9):
		print("Please enter a value between 1 and 10\n") 
		choice = int(input(">> "))

	# If the user selects a square that already has an "X" or "O", display an error message and prompt the user to reenter again
	if choices[choice - 1] == 'X' or choices[choice - 1] == 'O':
		print("illegal move, please try again")
		continue

	# Put an "X" or an "O" in the square that the user selected
	if playerOneTurn:
		choices[choice - 1] = 'X'
	else:
		choices[choice - 1] = 'O'

	# Display the Tic-tac-toe board
	print('\n -----')
	print('|' + choices[0] + '|' + choices[1] + '|' + choices[2] + '|')
	print(' -----')
	print('|' + choices[3] + '|' + choices[4] + '|' + choices[5] + '|')
	print(' -----')
	print('|' + choices[6] + '|' + choices[7] + '|' + choices[8] + '|')
	print(' -----\n')

	# Check each row and column starting from column 1, row 1 to column 3 row 3 to see if there are three X's or three O's.
	for x in range(0, 3):
		y = x * 3
		if (choices[y] == choices[(y + 1)] and choices[y] == choices[(y + 2)]):
			winner = True
	if (choices[x] == choices[(x + 3)] and choices[x] == choices[(x + 6)]):
		winner = True

	# Check each of the two diagonals to see if there are three Xs or three Os
	if((choices[0] == choices[4] and choices[0] == choices[8]) or 
	   (choices[2] == choices[4] and choices[4] == choices[6])):
		winner = True

	# Assign next player's turn
	playerOneTurn = not playerOneTurn

# Print the winner
print("Player " + str(int(playerOneTurn + 1)) + " wins!\n")